Beaded Friction
A bead slides without friction around a loop-the-loop. The bead is released from a height of 20.6 m from the b?
A bead slides without friction around a loop-the-loop. The bead is released from a height of 20.6 m from the bottom of the loop-the-loop which has a radius 6 m. The acceleration of gravity is 9.8 m/s2. What is its speed at point A. Answer in m/s
There's no diagram, so assuming point A is at the bottom of the loop:
initial gravitational potential energy = final kinetic energy
mgh = mv^2/2
v = sqrt(2gh)
v = sqrt[2(9.8 m/s^2)(20.6 m)]
v = 20 m/s
If point A is somewhere along the bottom radial portion and it makes an angle θ with the vertical, the conservation of energy calculation above still applies, except h = 20.6 - 6(1 - cosθ) m.
Chain Drop - Relativistic Reference Frame
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